Optimal. Leaf size=72 \[ -\frac {448 \sqrt {5 x+3}}{363 \sqrt {1-2 x}}+\frac {49 \sqrt {5 x+3}}{66 (1-2 x)^{3/2}}+\frac {9 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{2 \sqrt {10}} \]
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Rubi [A] time = 0.02, antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {89, 78, 54, 216} \begin {gather*} -\frac {448 \sqrt {5 x+3}}{363 \sqrt {1-2 x}}+\frac {49 \sqrt {5 x+3}}{66 (1-2 x)^{3/2}}+\frac {9 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{2 \sqrt {10}} \end {gather*}
Antiderivative was successfully verified.
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Rule 54
Rule 78
Rule 89
Rule 216
Rubi steps
\begin {align*} \int \frac {(2+3 x)^2}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx &=\frac {49 \sqrt {3+5 x}}{66 (1-2 x)^{3/2}}-\frac {1}{66} \int \frac {\frac {599}{2}+297 x}{(1-2 x)^{3/2} \sqrt {3+5 x}} \, dx\\ &=\frac {49 \sqrt {3+5 x}}{66 (1-2 x)^{3/2}}-\frac {448 \sqrt {3+5 x}}{363 \sqrt {1-2 x}}+\frac {9}{4} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=\frac {49 \sqrt {3+5 x}}{66 (1-2 x)^{3/2}}-\frac {448 \sqrt {3+5 x}}{363 \sqrt {1-2 x}}+\frac {9 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{2 \sqrt {5}}\\ &=\frac {49 \sqrt {3+5 x}}{66 (1-2 x)^{3/2}}-\frac {448 \sqrt {3+5 x}}{363 \sqrt {1-2 x}}+\frac {9 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{2 \sqrt {10}}\\ \end {align*}
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Mathematica [A] time = 0.06, size = 64, normalized size = 0.89 \begin {gather*} -\frac {70 (51-256 x) \sqrt {5 x+3}+3267 \sqrt {10} (2 x-1)^{3/2} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )}{7260 (1-2 x)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.10, size = 75, normalized size = 1.04 \begin {gather*} -\frac {7 \left (\frac {93 (1-2 x)}{5 x+3}-14\right ) (5 x+3)^{3/2}}{726 (1-2 x)^{3/2}}-\frac {9 \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}} \sqrt {1-2 x}}{\sqrt {5 x+3}}\right )}{2 \sqrt {10}} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.54, size = 86, normalized size = 1.19 \begin {gather*} -\frac {3267 \, \sqrt {10} {\left (4 \, x^{2} - 4 \, x + 1\right )} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 140 \, {\left (256 \, x - 51\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14520 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.06, size = 58, normalized size = 0.81 \begin {gather*} \frac {9}{20} \, \sqrt {10} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + \frac {7 \, {\left (256 \, \sqrt {5} {\left (5 \, x + 3\right )} - 1023 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}}{18150 \, {\left (2 \, x - 1\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 103, normalized size = 1.43 \begin {gather*} \frac {\left (13068 \sqrt {10}\, x^{2} \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-13068 \sqrt {10}\, x \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )+35840 \sqrt {-10 x^{2}-x +3}\, x +3267 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-7140 \sqrt {-10 x^{2}-x +3}\right ) \sqrt {5 x +3}\, \sqrt {-2 x +1}}{14520 \left (2 x -1\right )^{2} \sqrt {-10 x^{2}-x +3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.18, size = 62, normalized size = 0.86 \begin {gather*} \frac {9}{40} \, \sqrt {5} \sqrt {2} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) + \frac {49 \, \sqrt {-10 \, x^{2} - x + 3}}{66 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} + \frac {448 \, \sqrt {-10 \, x^{2} - x + 3}}{363 \, {\left (2 \, x - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (3\,x+2\right )}^2}{{\left (1-2\,x\right )}^{5/2}\,\sqrt {5\,x+3}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (3 x + 2\right )^{2}}{\left (1 - 2 x\right )^{\frac {5}{2}} \sqrt {5 x + 3}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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